y^2-4(y-5)2=0

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Solution for y^2-4(y-5)2=0 equation:


Simplifying
y2 + -4(y + -5) * 2 = 0

Reorder the terms:
y2 + -4(-5 + y) * 2 = 0

Reorder the terms for easier multiplication:
y2 + -4 * 2(-5 + y) = 0

Multiply -4 * 2
y2 + -8(-5 + y) = 0
y2 + (-5 * -8 + y * -8) = 0
y2 + (40 + -8y) = 0

Reorder the terms:
40 + -8y + y2 = 0

Solving
40 + -8y + y2 = 0

Solving for variable 'y'.

Begin completing the square.

Move the constant term to the right:

Add '-40' to each side of the equation.
40 + -8y + -40 + y2 = 0 + -40

Reorder the terms:
40 + -40 + -8y + y2 = 0 + -40

Combine like terms: 40 + -40 = 0
0 + -8y + y2 = 0 + -40
-8y + y2 = 0 + -40

Combine like terms: 0 + -40 = -40
-8y + y2 = -40

The y term is -8y.  Take half its coefficient (-4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
-8y + 16 + y2 = -40 + 16

Reorder the terms:
16 + -8y + y2 = -40 + 16

Combine like terms: -40 + 16 = -24
16 + -8y + y2 = -24

Factor a perfect square on the left side:
(y + -4)(y + -4) = -24

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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